Here are the relevant A-10 Tournament tiebreaker scenarios, as explained by Xavier blogger Shannon Russell (Click here for the full rundown). The Rams meet Temple Sunday in Philadelphia, while Saint Louis hosts La Salle Saturday.
Saint Louis – Currently the top seed. Can solidify No. 1 seed with a win over La Salle or a loss by VCU.
VCU – Currently the No. 2 seed. Can claim No. 1 seed with win over Temple and loss by Saint Louis. A Saint Louis win would give them the No. 2 seed whether they win or lose. A loss by VCU and a La Salle win (over SLU) would create three-way tie, with La Salle getting the No. 1 seed, SLU getting the No. 2 seed and VCU the No. 3 seed.
La Salle – Currently the No. 3 seed. Can claim No. 1 seed with win over Saint Louis and VCU loss. Can claim the No. 2 seed with a Saint Louis win and VCU win. (VCU to No. 1 seed, St. Louis to No. 3 seed.) A loss to Saint Louis and wins by Temple and two wins by Butler creates three-way tie. All three split with the other two, so it would go to record against best common opponents. If SLU won the A10, Temple would get the No. 3 seed, La Salle the 4 and Butler the 5. If VCU won the A10, La Salle would be the No. 3 seed, Temple the No. 4 seed and Butler the No. 5 seed. If La Salle loses and is tied with Butler only, La Salle would be the No. 3 seed, Butler the No. 4 seed. If La Salle loses and is tied with Temple only, Temple is the No. 3 seed and La Salle the No. 4 seed.